Question

fill in the blank question
the higher a spacecrafts orbit, the
the magnitude of free-fall acceleration, because of the
square relationship between ( r_e ) and ( r ).
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Explanation:

Free-fall acceleration \( g \) follows the inverse square law: \( g = \frac{GM}{r^2} \), where \( r \) is the distance from the Earth's center. A higher orbit means a larger \( r \), so \( g \) decreases. The relationship between \( g \) and \( r \) is inverse square.

Answer:

smaller; inverse