Question

3 fill in the blank complete the following decay equation. note: you will need to have a periodic table in hand. type your ar 152 type cs + answ type you 54 type your ar -1 what type of decay occurred: answer alpha beta e gamma +2

Explanation:

Step1: Determine the atomic number of Cs

From the periodic table, the atomic number of Cs (Cesium) is 55.

Step2: Calculate the atomic number of the parent nuclide

Using the conservation of atomic number: \(55+( - 1)=54\) (already given for the parent nuclide in the equation).

Step3: Calculate the mass number of the parent nuclide

Using the conservation of mass number: Let the mass number of the parent nuclide be \(A\). Then \(A = 152+0\) (since the mass number of a \(\beta^-\) particle (\(_{-1}^0e\)) is 0). So \(A = 152\).
The parent nuclide is \(_{54}^{152}Xe\) (Xenon - 152).

Step4: Identify the decay type

In \(\beta^-\) decay, a neutron in the nucleus is converted into a proton and an electron (the \(\beta^-\) particle). The general equation for \(\beta^-\) decay is \(_{Z}^{A}X
ightarrow_{Z + 1}^{A}Y+_{-1}^0e\). Here, \(Z\) (atomic number) changes from 54 to 55 (an increase of 1) and \(A\) (mass number) remains the same (152).

Answer:

The completed equation is \(_{54}^{152}Xe
ightarrow_{55}^{152}Cs+_{-1}^0e\). The type of decay is Beta (\(\beta^-\)) decay.