Question

figure p
(chemical structure with br and naoc(o)ch₃, reaction arrow)

Explanation:

Step1: Identify Reaction Type

The reactant is an alkyl bromide (1 - bromopentane, assuming the alkane chain is pentyl) and the reagent is sodium acetate ($\ce{NaOC(O)CH3}$). This is a nucleophilic substitution reaction, specifically $\ce{S_{N}2}$ (since the alkyl halide is primary, and the nucleophile is a carboxylate anion).

Step2: Determine Product

In an $\ce{S_{N}2}$ reaction, the nucleophile ($\ce{CH3COO^-}$ from $\ce{NaOC(O)CH3}$) attacks the carbon attached to the bromine (leaving group, $\ce{Br^-}$). The product will be the ester formed by substituting $\ce{Br}$ with $\ce{CH3COO^-}$. So the product is pentyl acetate, with the structure $\ce{CH3(CH2)4OC(O)CH3}$ (or more precisely, the alkyl group from the bromide attached to the oxygen of the acetate, i.e., $\ce{CH3CH2CH2CH2CH2OC(O)CH3}$).

Answer:

The product of the reaction is pentyl acetate (or 1 - pentyl acetate), with the chemical formula $\ce{CH3(CH2)4OC(O)CH3}$ (or structural formula showing the pentyl group attached to the oxygen of the acetate ester).