Question

in the figure below, n is parallel to o. find the values of x and z.
(3z + 30)°
x°
63°

Explanation:

Step1: Find the value of \(x\)

Since \(x\) and \(63^{\circ}\) are supplementary angles (they form a linear pair), we use the formula \(x + 63^{\circ}=180^{\circ}\).

$$x=180 - 63$$

$$x = 117$$

Step2: Find the value of \(z\)

Since \(n\parallel o\), the angle \((3z + 30)^{\circ}\) and \(63^{\circ}\) are corresponding angles. So \(3z+30 = 63\).
First, subtract \(30\) from both sides: \(3z=63 - 30\), \(3z = 33\).
Then divide both sides by \(3\): \(z=\frac{33}{3}\)

$$z = 11$$

Answer:

\(x = 117\), \(z = 11\)