Question

the figure below is dilated by a factor of 3 centered at the origin. plot the resulting image. click twice to plot a segment. click a segment to delete it. pre alg module 2 review due: october 14 at 8:00 pm grade: 75% dilations on the coordinate plane identify corresponding parts of similar figures scaled figures level 1 scaled figures level 2 answer attempt 1 out of 2

Explanation:

Step1: Recall dilation rule

For a dilation centered at the origin with scale - factor \(k\), if a point has coordinates \((x,y)\), the coordinates of its image are \((kx,ky)\). Here \(k = 3\).

Step2: Find new coordinates of trapezoid vertices

Let's assume the vertices of the trapezoid \(STUV\) have coordinates \(S(-3,-3)\), \(T(1,-3)\), \(U(3,0)\), \(V(1,2)\), \(W(-3,3)\).
For point \(S\): \(S'=(3\times(-3),3\times(-3))=(-9,-9)\)
For point \(T\): \(T'=(3\times1,3\times(-3))=(3,-9)\)
For point \(U\): \(U'=(3\times3,3\times0)=(9,0)\)
For point \(V\): \(V'=(3\times1,3\times2)=(3,6)\)
For point \(W\): \(W'=(3\times(-3),3\times3)=(-9,9)\)

Step3: Plot the new points

Plot the points \(S'(-9,-9)\), \(T'(3,-9)\), \(U'(9,0)\), \(V'(3,6)\), \(W'(-9,9)\) on the coordinate - plane and connect them to form the dilated trapezoid.

Answer:

Plot the points \((-9,-9)\), \((3,-9)\), \((9,0)\), \((3,6)\), \((-9,9)\) and connect them to form the dilated figure.