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Question
in the figure below, \\( \overline{ab} \cong \overline{ad} \\) and \\( \overline{ac} \\) bisects \\( \angle a \\). solve for \\( x \\). then, using that value, find the length of \\( \overline{ac} \\).
Step1: Use the property of congruent triangles
Since \(AB\cong AD\) and \(AC\) bisects \(\angle A\), \(\triangle ABC\cong\triangle ADC\) (by the Side - Angle - Side (SAS) congruence criterion). Then \(BC = DC\).
Set up the equation \(2x + 160=15x + 4\).
Step2: Solve the equation for \(x\)
Subtract \(2x\) from both sides: \(160 = 13x+4\).
Subtract \(4\) from both sides: \(156 = 13x\).
Divide both sides by \(13\): \(x = 12\).
Step3: Find the length of \(AC\)
Substitute \(x = 12\) into the expression for \(AC\) (\(AC=11x + 35\)).
\(AC=11\times12+35\).
First, calculate \(11\times12 = 132\).
Then \(AC=132 + 35=167\).
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\(x = 12\) and the length of \(\overline{AC}\) is \(167\).