Question

a fictional element named nivad ium is found to have three naturally occurring isotopes with the natural abundan

the calculated atomic mass of nivad ium is:
69.55 amu
23.18 amu
7.61 amu
22.83 amu
none of the above

Explanation:

Step1: Convert percentages to decimals

For the first isotope: \(45.00\%=0.45\)
For the second isotope: \(45.00\% = 0.45\)
For the third isotope: \(10.00\%=0.10\)

Step2: Calculate the contribution of each isotope

Contribution of first isotope: \(22.1760\times0.45 = 9.9792\)
Contribution of second isotope: \(23.1847\times0.45=10.433115\)
Contribution of third isotope: \(24.1934\times0.10 = 2.41934\)

Step3: Sum up the contributions

\(9.9792+10.433115 + 2.41934=22.831655\approx22.83\)

Answer:

22.83 amu