Question

1. as a falling objects speed increases, its potential energy increases and its decreases. drag the answers below into the grey placeholders above kinetic energy total energy reset answers

Explanation:

When a falling object's speed increases, its kinetic energy ($KE=\frac{1}{2}mv^{2}$, where $m$ is mass and $v$ is speed) increases. According to the law of conservation of energy (in the absence of non - conservative forces like air resistance in an ideal case, total energy $E = KE+PE$ is constant). If potential energy ($PE = mgh$, where $h$ is height) increases (which is incorrect in a normal free - fall where $h$ decreases and $PE$ should decrease, but assuming a mis - statement in the problem's first part), but if we consider the relationship between $KE$ and $PE$ in energy transfer, as one form of mechanical energy changes, the other changes inversely. Since the problem says "its potential energy increases", the other form (kinetic energy) cannot be the one that decreases. However, if we assume it's a mis - print and the object is rising (but the problem says falling), but based on the options given and the energy concepts: Kinetic energy is related to motion (speed) and potential energy is related to position. If there is an error in the first part (it should be potential energy decreases as height decreases for a falling object), but with the given options, using the energy conservation principle (total energy $E=KE + PE$), if there is a wrong statement about potential energy increasing, but if we just consider the inverse relationship between the two forms of mechanical energy (ignoring the height - related potential energy change for a second and just looking at the form of energy related to speed), but actually, for a falling object in reality, $PE=mgh$ ( $h$ decreases, so $PE$ decreases) and $KE=\frac{1}{2}mv^{2}$ ( $v$ increases, so $KE$ increases). But if we follow the problem's structure (wrong first part about $PE$ increasing), but among the options, total energy is conserved (constant) in an ideal case. So if one form (incorrectly said as $PE$ increasing) then the other form (kinetic energy) can't be, but total energy is constant.

Answer:

total energy