Question

fa25 math 125 - 09: precalculus i
homework: ch 1.2 operations with algebraic expressions
question 4, ar.3.14
combine terms. arrange your answer in descending order.
9b^5 + b^2 - b^3 - 6b^5 - 8b^2
the answer is (type in descending order)

Explanation:

Step1: Combine like - terms

Combine the terms with the same power of $b$. For the $b^5$ terms: $9b^5-6b^5 = 3b^5$. For the $b^2$ terms: $b^2-8b^2=-7b^2$. The $-b^3$ term remains as it is.

Step2: Arrange in descending order

Arrange the terms in descending order of the exponent of $b$. The highest - power term is $b^5$, then $b^3$, and then $b^2$. So the expression becomes $3b^5 - b^3-7b^2$.

Answer:

$3b^5 - b^3-7b^2$