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Question
extra practice problems
- -5x - 8 + 12 = 34
- -14 = 6x - 4 - 7x
- 4(x - 2) + 2x = 40
- 6(x - 1) + 11 = 53
Problem 22:
Step 1: Simplify constants
Simplify \(-8 + 12\) to get \(4\). The equation becomes \(-5x + 4 = 34\).
Step 2: Subtract 4 from both sides
Subtract \(4\) from both sides: \(-5x + 4 - 4 = 34 - 4\), so \(-5x = 30\).
Step 3: Divide by -5
Divide both sides by \(-5\): \(\frac{-5x}{-5}=\frac{30}{-5}\), so \(x = -6\).
Problem 23:
Step 1: Combine like terms
Combine \(6x - 7x\) to get \(-x\). The equation becomes \(-14 = -x - 4\).
Step 2: Add 4 to both sides
Add \(4\) to both sides: \(-14 + 4 = -x - 4 + 4\), so \(-10 = -x\).
Step 3: Multiply by -1
Multiply both sides by \(-1\): \(x = 10\).
Problem 25:
Step 1: Distribute the 4
Distribute \(4\) in \(4(x - 2)\): \(4x - 8 + 2x = 40\).
Step 2: Combine like terms
Combine \(4x + 2x\) to get \(6x\). The equation becomes \(6x - 8 = 40\).
Step 3: Add 8 to both sides
Add \(8\) to both sides: \(6x - 8 + 8 = 40 + 8\), so \(6x = 48\).
Step 4: Divide by 6
Divide both sides by \(6\): \(\frac{6x}{6}=\frac{48}{6}\), so \(x = 8\).
Problem 26:
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s:
- Problem 22: \(x = -6\)
- Problem 23: \(x = 10\)
- Problem 25: \(x = 8\)
- Problem 26: \(x = 8\)