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extra practice level up your skills! mixed proofs proof write the corre…

Question

extra practice level up your skills! mixed proofs proof write the correct statements and reasons to complete the two - column proof. given: \\( \overline { m p } \cong \overline { l p } \\) \\( \overline { ln } \cong \overline { m o } \\) prove: \\( p n = p o \\) proof: 1. \\( \overline { m p } \cong \overline { l p } \\) \\( \overline { ln } \cong \overline { m o } \\) 2. 3. \\( m o = m p + p o \\) \\( l n = l p + p n \\) 4. \\( l p + p n = m p + p o \\) 5. \\( l p + p n = l p + p o \\) 6. basket of choices substitution property segment addition postulate \\( p n = p o \\) \\( m p = l p, l n = m o \\) given substitution property

Explanation:

Step1: Reasons for Statement 1

The first statement is given in the problem. So the reason for statement 1 is "Given".

Step2: Statements for Reason 2

Since the reason is "Definition of ≅ segments", the statement should be \(MP = LP\) and \(LN=MO\).

Step3: Reasons for Statement 3

The Segment Addition Postulate states that if \(A - B - C\), then \(AC=AB + BC\). So the reason for statement 3 is "Segment Addition Postulate".

Step4: Reasons for Statement 4

Since \(LN = MP+PO\) and \(LN = LP + PN\) (from statements 1 - 3), by substitution (if \(a=b\) and \(a = c\), then \(b = c\)), the reason for statement 4 is "Substitution Property".

Step5: Reasons for Statement 5

Since \(MP = LP\) (from statement 2), we substitute \(MP\) with \(LP\) in \(MP+PO\). So the reason for statement 5 is "Substitution Property".

Step6: Statements for Reason 6

Starting from \(LP + PN=LP + PO\), using the Subtraction Property of Equality (\(a + b=a + c\) implies \(b = c\) when we subtract \(a\) from both sides), we get \(PN=PO\).

Answer:

StatementsReasons
2. \(MP = LP\), \(LN = MO\)2. Definition of \(\cong\) segments
3. \(MO=MP + PO\), \(LN=LP + PN\)3. Segment Addition Postulate
4. \(LP + PN=MP + PO\)4. Substitution Property
5. \(LP + PN=LP + PO\)5. Substitution Property
6. \(PN = PO\)6. Subtraction Property of Equality