Question

exponents and polynomials
factoring a difference of squares in one variable: advanced
factor.
36 - 49v²

Explanation:

Step1: Recall difference of squares formula

The formula for factoring a difference of squares is $a^2 - b^2 = (a - b)(a + b)$.

Step2: Identify a and b

For the expression $36 - 49v^2$, we can rewrite it as $6^2 - (7v)^2$. Here, $a = 6$ and $b = 7v$.

Step3: Apply the formula

Using the difference of squares formula, we substitute $a = 6$ and $b = 7v$ into $(a - b)(a + b)$. So we get $(6 - 7v)(6 + 7v)$.

Answer:

$(6 - 7v)(6 + 7v)$