Question

explain how you would find the volume of an irregular object using water displacement.

Explanation:

First, take a graduated - cylinder and fill it with a known volume of water ($V_1$). Then, carefully place the irregular object into the water so that it is completely submerged. The water level will rise. Record the new volume of water with the object submerged ($V_2$). The volume of the irregular object is equal to the difference between the final volume and the initial volume, i.e., $V = V_2 - V_1$. This method works because the volume of water displaced by the object is equal to the volume of the object itself according to Archimedes' principle.

Answer:

First, measure the initial volume of water in a graduated - cylinder ($V_1$). Then, submerge the irregular object completely in the water and measure the new volume ($V_2$). The volume of the object is $V = V_2 - V_1$.