Question

in an experiment, naoh and hcl are mixed. based on the graph, what is the change in temperature of the mixture if the initial temperature of the naoh was 23.0°c and the initial temperature of the hcl was 25.2°c?

reaction 1: naoh + hcl

12.7°c
10.4°c
1.3°c
13.2°c

Explanation:

Step1: Find the initial temperature of the mixture

Assume equal volumes of NaOH and HCl (since not given otherwise). The initial temperature of the mixture \(T_{initial}=\frac{23.0 + 25.2}{2}=\frac{48.2}{2}=24.1^{\circ}C\)

Step2: Find the maximum temperature from the graph

From the graph, the maximum temperature \(T_{max} = 37.3^{\circ}C\)

Step3: Calculate the change in temperature

The change in temperature \(\Delta T=T_{max}-T_{initial}\)
\(\Delta T = 37.3-24.1=13.2^{\circ}C\)

Answer:

13.2°C