Question

exit quiz 2 of 28 grade question (refer to figure 2.) if an suas weighs 50 pounds, what approximate weight would the suas structure be required to support during a 30 degree banked turn while maintaining altitude? view figures answer choices 60 pounds. 45 pounds. 30 pounds.

Explanation:

Step1: Identify the formula

The load factor $n$ in a banked - turn is given by $n=\frac{1}{\cos\theta}$, where $\theta$ is the bank angle.

Step2: Calculate the load factor

Given $\theta = 30^{\circ}$, then $\cos\theta=\cos30^{\circ}=\frac{\sqrt{3}}{2}\approx0.866$. So, $n=\frac{1}{\cos30^{\circ}}=\frac{1}{0.866}\approx1.15$.

Step3: Calculate the required support weight

The weight of the sUAS is $W = 50$ pounds. The required support weight $W_{required}=n\times W$. Substituting the values, we get $W_{required}=1.15\times50 = 57.5\approx60$ pounds.

Answer:

60 pounds.