Question

1 essay 1 point a student lifts a 1.2 - kg bag from her desk, which is 0.59 - m high, to a locker that is 2.9 - m high. what is the gravitational potential energy of the bag relative to the desk? edit format table

Explanation:

Step1: Determine the height difference

The height difference \(h\) between the locker and the desk is \(h = 2.9 - 0.59=2.31\space m\)

Step2: Use the gravitational potential energy formula

The formula for gravitational potential energy \(U = mgh\), where \(m = 1.2\space kg\), \(g = 9.8\space m/s^{2}\), and \(h = 2.31\space m\)
Substitute the values: \(U=1.2\times9.8\times2.31\)
First calculate \(1.2\times9.8 = 11.76\)
Then \(11.76\times2.31=27.1656\space J\)

Answer:

\(27\space J\) (rounded to two significant figures)