Question

the equation of a certain circle in the standard $(x,y)$ coordinate plane is $(x - 11)^2+(y - 4)^2 = 9$. what is the radius, in coordir
a. 3
b. 4
c. 11
d. 81

Explanation:

Step1: Recall the standard form of a circle's equation

The standard form of a circle's equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.

Step2: Compare the given equation with the standard form

Given \((x - 11)^2+(y - 4)^2 = 9\). Since \(r^2=9\), then \(r=\sqrt{9}\).

Answer:

A. 3