Question

enrique is given information about a satellite orbiting earth.
$r = 3.8\times10^{8}m$
$t = 18$ days
in order to calculate the tangential speed of the satellite, what should enrique do first?
convert the radius to kilometers
convert the orbital period to seconds
find the square root of the radius
find the square root of the orbital period

Explanation:

Step1: Recall the formula for tangential speed

The formula for the tangential speed \(v\) of an object in circular motion is \(v=\frac{2\pi r}{T}\), where \(r\) is the radius of the circular path and \(T\) is the period of the motion. In the International System of Units (SI), the standard unit for speed is meters per second (\(m/s\)). The radius \(r = 3.8\times10^{8}\text{ m}\) is already in SI units for length.

Step2: Analyze the unit of the period

The period \(T = 18\) days. Since the SI unit for time in the formula \(v=\frac{2\pi r}{T}\) is seconds, we need to convert the time from days to seconds. We know that \(1\) day \(= 24\) hours, \(1\) hour \(= 60\) minutes and \(1\) minute \(= 60\) seconds. So \(1\) day \(=24\times60\times60=86400\) seconds.

Answer:

convert the orbital period to seconds