Question

emission spectrometer calibration
your selected emission line corresponds to one of the transitions between the 1st and 5th energy levels. lets figure out what the wavelength for this transition should be.
to begin, calculate the energy of each of the levels.
energy for n=1
-2.18e - 18 j
energy for n=5
-8.72e - 20 j
now calculate the energy of the photon that is emitted during this transition.
e=
enter a number... j
how to calculate energy of a photon

Explanation:

Step1: Determine the energy difference formula

The energy of the photon emitted during a transition between energy levels \(n_i\) and \(n_f\) is given by \(E = E_{n_i}-E_{n_f}\). Here, \(n_i = 5\) and \(n_f=1\).

Step2: Substitute the given energy values

We are given \(E_1=- 2.1\times10^{-18}\text{ J}\) and \(E_5=-8.72\times 10^{-20}\text{ J}\). Then \(E=E_5 - E_1\).

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Answer:

\(2.01\times 10^{-18}\text{ J}\)