QUESTION IMAGE
Question
ections: simplify the following expressions by combining like terr corresponding coefficient (note: write subtraction as addition each blank of the “secret code” with the correct letter.
problem\tanswer
$4(x - 5)+3(x + 3)$
\\(\dfrac{\quad\quad}{d}x + \dfrac{\quad\quad}{g}\\)
$14x - 3y + 2y - 5x$
\\(\dfrac{\quad\quad}{m}x + \dfrac{\quad\quad}{u}y\\)
$2x(4 - 3x)$
\\(\dfrac{\quad\quad}{b}x^2 + \dfrac{\quad\quad}{q}x\\)
$6x^2 - 3(x + x^2)$
\\(\dfrac{\quad\quad}{x}x^2 + \dfrac{\quad\quad}{c}x\\)
$5x - 6x + 4x - x$
\\(\dfrac{\quad\quad}{n}x\\)
$-x(4x + 3y)+x - 4xy$
\\(\dfrac{\quad\quad}{t}x^2 + \dfrac{\quad\quad}{l}xy + \dfrac{\quad\quad}{y}x\\)
$7x + 2(5 - x)$
\\(\dfrac{\quad\quad}{p}x + \dfrac{\quad\quad}{h}\\)
$3x - 5x(1 + y)$
\\(\dfrac{\quad\quad}{r}x + \dfrac{\quad\quad}{a}xy\\)
$7x + 2(3x)-3(x + 2x)-4x$
\\(\dfrac{\quad\quad}{o}x\\)
$3x(2 - 3x - 4x^2)$
\\(\dfrac{\quad\quad}{s}x^3 + \dfrac{\quad\quad}{e}x^2 + \dfrac{\quad\quad}{i}x\\)
Problem 1: \( 4(x - 5) + 3(x + 3) \)
Step 1: Distribute the coefficients
\( 4(x - 5) = 4x - 20 \) and \( 3(x + 3) = 3x + 9 \)
Step 2: Combine like terms
\( (4x + 3x) + (-20 + 9) = 7x - 11 \)
Step 1: Combine \( x \)-terms
\( 14x - 5x = 9x \)
Step 2: Combine \( y \)-terms
\( -3y + 2y = -y \)
Step 1: Distribute \( 2x \)
\( 2x \cdot 4 - 2x \cdot 3x = 8x - 6x^2 \)
Step 2: Rearrange terms
\( -6x^2 + 8x \)
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For \( D \) (coefficient of \( x \)): \( 7 \)
For \( G \) (constant term): \( -11 \)