Question

for each reaction, write the chemical formulae of the oxidized reactants in the space provided. write the chemical formulae of the reduced reactants in the space provided.

fei₂(aq) + mg(s) → mgi₂(aq) + fe(s)
reactants oxidized:
reactants reduced:

cucl₂(aq) + mg(s) → mgcl₂(aq) + cu(s)
reactants oxidized:
reactants reduced:

2agno₃(aq) + mg(s) → 2ag(s) + mg(no₃)₂(aq)
reactants oxidized:
reactants reduced:

Explanation:

Step1: Determine oxidation states

Oxidation state of \(Mg\) in \(Mg(s)\) is \(0\). In \(MgI_2(aq)\), \(Mg\) is \(+2\). Oxidation state of \(Fe\) in \(FeI_2(aq)\) is \(+2\), in \(Fe(s)\) is \(0\).
For \(CuCl_2(aq)+Mg(s)\to MgCl_2(aq)+Cu(s)\), \(Mg\) goes from \(0\) to \(+2\), \(Cu\) from \(+2\) to \(0\).
For \(2AgNO_3(aq)+Mg(s)\to 2Ag(s)+Mg(NO_3)_2(aq)\), \(Mg\) from \(0\) to \(+2\), \(Ag\) from \(+1\) to \(0\).

Step2: Identify oxidized and reduced reactants

Oxidized reactant: loses electrons (oxidation state increases). Reduced reactant: gains electrons (oxidation state decreases).

Answer:

• For \(FeI_2(aq)+Mg(s)\to MgI_2(aq)+Fe(s)\):
• reactants oxidized: \(Mg\)
• reactants reduced: \(FeI_2\)
• For \(CuCl_2(aq)+Mg(s)\to MgCl_2(aq)+Cu(s)\):
• reactants oxidized: \(Mg\)
• reactants reduced: \(CuCl_2\)
• For \(2AgNO_3(aq)+Mg(s)\to 2Ag(s)+Mg(NO_3)_2(aq)\):
• reactants oxidized: \(Mg\)
• reactants reduced: \(AgNO_3\)