Question

for each problem, find the: x and y intercepts, x - coordinates of the critical points, open intervals where the function is increasing and decreasing, x - coordinates of the inflection points, open intervals where function is concave up and concave down, and relative minima and maxima. using this information, sketch the graph of the function.

1. ( y =-\frac{x^{3}}{3}+x^{2} )

Explanation:

Step1: Find x-intercepts

Set $y=0$: $-\frac{x^3}{3} + x^2 = 0 \Rightarrow x^2(-\frac{x}{3} + 1) = 0 \Rightarrow x=0$ or $x=3$

Step2: Find y-intercept

Set $x=0$: $y=0$

Step3: Find critical points

Compute $y'$: $y' = -x^2 + 2x$
Set $y'=0$: $-x(x-2)=0 \Rightarrow x=0$ or $x=2$

Step4: Increasing/decreasing intervals

Test $y'$:

• $x<0$: $y'<0$ (decreasing)
• $00$ (increasing)
• $x>2$: $y'<0$ (decreasing)

Step5: Relative extrema

• $x=0$: decreasing→increasing (min)
• $x=2$: increasing→decreasing (max)

Step6: Find inflection points

Compute $y''$: $y'' = -2x + 2$
Set $y''=0$: $x=1$

Step7: Concavity intervals

Test $y''$:

• $x<1$: $y''>0$ (concave up)
• $x>1$: $y''<0$ (concave down)

Answer:

x-intercepts: $0, 3$; y-intercept: $0$; critical points: $0, 2$; increasing: $(0,2)$; decreasing: $(-\infty,0)\cup(2,\infty)$; inflection point: $1$; concave up: $(-\infty,1)$; concave down: $(1,\infty)$; relative min at $x=0$, relative max at $x=2$
(Graph: Plot intercepts (0,0),(3,0); min at (0,0), max at (2, 4/3); inflection at (1, 2/3); curve concave up left of x=1, concave down right of x=1; decreasing before 0, increasing between 0&2, decreasing after 2)