Question

for each of the following, write the formula of the covalent compound:

1. antimony tribromide
2. iodine pentafluoride
3. dinitrogen trioxide
4. phosphorous triiodide

Explanation:

Step1: Naming rules for covalent compounds

For covalent compounds, the prefixes indicate the number of atoms of each element. For example, "tri -" means 3, "penta -" means 5, "di -" means 2.

Step2: Writing formulas for each compound

1. Antimony tribromide:

• Antimony is \(Sb\), "tribromide" means 3 bromine (\(Br\)) atoms. So the formula is \(SbBr_{3}\).

1. Iodine pentafluoride:

• Iodine is \(I\), "pentafluoride" means 5 fluorine (\(F\)) atoms. So the formula is \(IF_{5}\).

1. Dinitrogen trioxide:

• "Dinitrogen" means 2 nitrogen (\(N\)) atoms, "trioxide" means 3 oxygen (\(O\)) atoms. So the formula is \(N_{2}O_{3}\).

1. Phosphorus triiodide:

• Phosphorus is \(P\), "triiodide" means 3 iodine (\(I\)) atoms. So the formula is \(PI_{3}\).

Answer:

1. \(SbBr_{3}\)
2. \(IF_{5}\)
3. \(N_{2}O_{3}\)
4. \(PI_{3}\)