Question

during a game of pool, a cue ball travels to the left with 70 n of force and collides with the four ball moving with a force of 50 n to the right. if you assign a negative value to the force moving to the right, what is the net force of this system? (1 point) 20 n -20 n 20 m/s2 120 n

Explanation:

Step1: Assign values to forces

Let the force to the left be positive. So, \(F_1 = 70N\) (cue - ball force), and \(F_2=- 50N\) (four - ball force as it is to the right).

Step2: Calculate net force

The formula for net force \(F_{net}=F_1 + F_2\). Substitute the values: \(F_{net}=70+( - 50)\).
Using the rule \(a+( - b)=a - b\), we get \(F_{net}=70 - 50\).

Answer:

\(20N\)