Question

1. a drop of water goes over a 250 m waterfall at a speed of 6.7 m/s. how far has the droplet fallen after 4 seconds? 125 m 78.48 m 156.96 m 19.62 m

Explanation:

Step1: Identify the kinematic equation

The kinematic equation for vertical displacement \(h = v_0t+\frac{1}{2}gt^2\). Here, the initial vertical velocity \(v_0 = 0\ m/s\) (assuming the drop just goes over the waterfall and has no initial vertical push), \(g = 9.81\ m/s^2\), and \(t = 4\ s\).

Step2: Substitute the values into the equation

Since \(v_0 = 0\ m/s\), the equation simplifies to \(h=\frac{1}{2}gt^2\). Substitute \(g = 9.81\ m/s^2\) and \(t = 4\ s\) into the formula:

$$
LATEXBLOCK0
$$

Answer:

78.48 m