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Question
2.) draw the 6th figure.
Step1: Analyze the pattern
The first figure has 1 square. The second figure has 3 squares (2 + 1). The third figure has 5 squares (3+ 2). The number of squares in the $n$ - th figure follows the arithmetic - sequence formula $a_n=2n - 1$. Also, the vertical part has $n$ squares and the horizontal part (excluding the square that is common with the vertical part) has $n - 1$ squares.
Step2: Determine the number of squares for the 6th figure
For $n = 6$, using the formula $a_n=2n - 1$, we have $a_6=2\times6 - 1=11$ squares. The vertical part will have 6 squares and the horizontal part (excluding the common square) will have 5 squares.
Step3: Draw the figure
Draw a vertical stack of 6 squares and attach a horizontal row of 5 squares to the bottom - right of the vertical stack.
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Draw a vertical stack of 6 squares with a horizontal row of 5 squares attached to the bottom - right of the vertical stack.