Question

drag and drop the solutions given below into their correct places.

\\x^2 + 5x + 6 = 0\\
\\x^2 - x - 6 = 0\\
\\x^2 + x - 6 = 0\\
\\x^2 - 5x + 6 = 0\\

options:
\\x = 2, -3\\
\\x = 3, -2\\
\\x = 3, 2\\
\\x = -2, -3\\

Explanation:

Solve the first quadratic equation

Using the Factoring Quadratic Trinomials and Quadratic Equations knowledge points

$$
LATEXBLOCK0
$$

Solve the second quadratic equation

Using the Factoring Quadratic Trinomials and Quadratic Equations knowledge points

$$
LATEXBLOCK1
$$

Solve the third quadratic equation

Using the Factoring Quadratic Trinomials and Quadratic Equations knowledge points

$$
LATEXBLOCK2
$$

Solve the fourth quadratic equation

Using the Factoring Quadratic Trinomials and Quadratic Equations knowledge points

$$
LATEXBLOCK3
$$

Answer:

No.	Problem	Answer
2	\(x^2 - x - 6 = 0\)	\(x = 3, -2\)
3	\(x^2 + x - 6 = 0\)	\(x = 2, -3\)
4	\(x^2 - 5x + 6 = 0\)	\(x = 3, 2\)