Question

1. the double replacement reaction is between aqueous lead(ii) nitrate and potassium iodide:

pb(no₃)₂ + ki → ?

identify the possible products of this reaction.

i need a hint

select all that apply:

pbk

k(no₃)₂

kno₃

pbi

pbi₂

(no₃)₂i

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Explanation:

Step1: Recall double replacement rules

In a double replacement reaction, cations and anions swap. For $\ce{Pb(NO_{3})_{2}}$ (cation $\ce{Pb^{2+}}$, anion $\ce{NO^{-}_{3}}$) and $\ce{KI}$ (cation $\ce{K^{+}}$, anion $\ce{I^{-}}$), swap to get new compounds.

Step2: Determine formulas

• $\ce{Pb^{2+}}$ pairs with $\ce{I^{-}}$: Charge balance gives $\ce{PbI_{2}}$ (2 $\ce{I^{-}}$ for $\ce{Pb^{2+}}$).
• $\ce{K^{+}}$ pairs with $\ce{NO^{-}_{3}}$: Charge balance gives $\ce{KNO_{3}}$ (1 $\ce{NO^{-}_{3}}$ for $\ce{K^{+}}$).

Answer:

The possible products are $\ce{KNO_{3}}$ and $\ce{PbI_{2}}$, so the correct options are:

• $\ce{KNO_{3}}$
• $\ce{PbI_{2}}$