and domain, find the range values.
2. $y = x^2 - 2x$; domain $= \{-3, 0, 5\}$

Question

Accepted Answer

# Explanation:
## Step1: Substitute $ x = -3 $ into the function
To find the corresponding $ y $-value when $ x = -3 $, we substitute $ x = -3 $ into $ y = x^2 - 2x $.
$$
\begin{align*}
y&=(-3)^2 - 2\times(-3)\
&=9 + 6\
&=15
\end{align*}
$$
## Step2: Substitute $ x = 0 $ into the function
Substitute $ x = 0 $ into $ y = x^2 - 2x $.
$$
\begin{align*}
y&=0^2 - 2\times0\
&=0 - 0\
&=0
\end{align*}
$$
## Step3: Substitute $ x = 5 $ into the function
Substitute $ x = 5 $ into $ y = x^2 - 2x $.
$$
\begin{align*}
y&=5^2 - 2\times5\
&=25 - 10\
&=15
\end{align*}
$$
# Answer:
The range values are $\{0, 15\}$

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QUESTION IMAGE

Question

Explanation:

Step1: Substitute \( x = -3 \) into the function

Step2: Substitute \( x = 0 \) into the function

Step3: Substitute \( x = 5 \) into the function

Answer: