Question

doblan un alambre primero en forma cuadrada. cada lado del cuadrado mide 7 in de largo. luego lo doblando en forma de rectángulo. si la longitud del rectángulo es 11 in, ¿cuál es el ancho?

Explanation:

Step1: Find the perimeter of the square.

The perimeter of a square is given by $P = 4s$, where $s$ is the side - length. Here, $s = 7$ in, so $P=4\times7 = 28$ in.

Step2: Use the perimeter formula for the rectangle.

The perimeter of a rectangle is $P = 2(l + w)$, where $l$ is the length and $w$ is the width. We know $P = 28$ in and $l = 11$ in. Substitute into the formula: $28=2(11 + w)$.
First, divide both sides of the equation by 2: $\frac{28}{2}=\frac{2(11 + w)}{2}$, which simplifies to $14 = 11+w$.
Then, solve for $w$: $w=14 - 11=3$ in.

Answer:

3 in