Question

divide.
\\((x^2 + 3x - 40) \div (x - 5)\\)

subtract.
there are no further terms to bring down. this division has a remainder of zero.

thus, \\((x^2 + 3x - 40) \div (x - 5) = \square\\)

Explanation:

Identify the division problem

$$ (x^2 + 3x - 40) \div (x - 5) $$

Read the quotient from the division steps

$$ \text{Quotient} = x + 8 $$

Verify the result

$$ (x - 5)(x + 8) = x^2 + 8x - 5x - 40 = x^2 + 3x - 40 $$

Answer:

Thus, \((x^2 + 3x - 40) \div (x - 5) =\) <blank>\(x + 8\)</blank>