Question

distance and the pythagorean theorem practice
complete this assessment to review what youve learned. it will not count toward your grade.
find the distance between $(-8,-3)$ and $(-2,-5)$. round your answer to the nearest hundredth, if necessary. (1 point)
units
check answer remaining attempts : 3

Explanation:

Step1: Identify the coordinates

Let \((x_1,y_1)=(-8,-3)\) and \((x_2,y_2)=(-2,-5)\)

Step2: Use the distance formula \(d = \sqrt{(x_2 - x_1)^2+(y_2 - y_1)^2}\)

Substitute the values: \(x_2 - x_1=-2-(-8)=6\), \(y_2 - y_1=-5 - (-3)=-2\)

Step3: Calculate \((x_2 - x_1)^2+(y_2 - y_1)^2\)

\((6)^2+(-2)^2=36 + 4=40\)

Step4: Find the square root

\(d=\sqrt{40}\approx6.32\)

Answer:

\(6.32\)