Question

directions: write the correct name for the following chemic

1. kno₃ =
2. cucl₂ =
3. na₂so₄ =
4. alcl₃ =
5. ca(oh)₂ =
6. na₃po₄ =
7. so₃ =
8. feo =
9. cuo =
10. pbcl₄ =
11. mno₂ =
12. nh₄cl =
13. na₂co₃ =

Explanation:

1. For \(KNO_3\), \(K\) is potassium, \(NO_3^-\) is nitrate ion. So it's potassium nitrate.
2. \(CuCl_2\), \(Cu\) has +2 oxidation state here (as \(Cl^-\) is -1 and there are two \(Cl\) atoms). So it's copper(II) chloride.
3. \(Na_2SO_4\), \(Na\) is sodium, \(SO_4^{2 -}\) is sulfate ion. So it's sodium sulfate.
4. \(AlCl_3\), \(Al\) is aluminum, \(Cl\) is chloride. So it's aluminum chloride.
5. \(Ca(OH)_2\), \(Ca\) is calcium, \(OH^-\) is hydroxide. So it's calcium hydroxide.
6. \(Na_3PO_4\), \(Na\) is sodium, \(PO_4^{3 -}\) is phosphate. So it's sodium phosphate.
7. \(SO_3\), it's a covalent compound. So it's sulfur trioxide.
8. \(FeO\), \(Fe\) has +2 oxidation state (as \(O^{2 -}\) is -2). So it's iron(II) oxide.
9. \(CuO\), \(Cu\) has +2 oxidation state (as \(O^{2 -}\) is -2). So it's copper(II) oxide.
10. \(PbCl_4\), \(Pb\) has +4 oxidation state (as \(Cl^-\) is -1 and there are four \(Cl\) atoms). So it's lead(IV) chloride.
11. \(MnO_2\), \(Mn\) has +4 oxidation state (as \(O^{2 -}\) is -2 and there are two \(O\) atoms). So it's manganese(IV) oxide.
12. \(NH_4Cl\), \(NH_4^+\) is ammonium, \(Cl^-\) is chloride. So it's ammonium chloride.
13. \(Na_2CO_3\), \(Na\) is sodium, \(CO_3^{2 -}\) is carbonate. So it's sodium carbonate.

Answer:

1. potassium nitrate
2. copper(II) chloride
3. sodium sulfate
4. aluminum chloride
5. calcium hydroxide
6. sodium phosphate
7. sulfur trioxide
8. iron(II) oxide
9. copper(II) oxide
10. lead(IV) chloride
11. manganese(IV) oxide
12. ammonium chloride
13. sodium carbonate