Question

the diameter of the sun is $4.5 \times 10^6$ km. the diameter of the fictional planet icuro is $0.5 \times 10^3$ km. how many icuros laid end to end would fit along the diameter of the sun? \boxed{} icuros

Explanation:

Step1: Identify the formula

To find the number of Icuros that fit along the Sun's diameter, we divide the Sun's diameter by Icuro's diameter. The formula is \( n=\frac{D_{\text{Sun}}}{D_{\text{Icuro}}} \), where \( D_{\text{Sun}} = 4.5\times10^{6}\) km and \( D_{\text{Icuro}}=0.5\times 10^{3}\) km.

Step2: Substitute the values

Substitute the given values into the formula: \( n=\frac{4.5\times 10^{6}}{0.5\times 10^{3}} \)

Step3: Simplify the expression

First, divide the coefficients: \( \frac{4.5}{0.5}=9 \). Then, use the rule of exponents \( \frac{10^{a}}{10^{b}} = 10^{a - b}\), so \( \frac{10^{6}}{10^{3}}=10^{6 - 3}=10^{3}\). Multiply the results: \( 9\times10^{3}=9000 \)

Answer:

9000