Question

determining conditional probabilities of blood types. the table displays the distribution of blood types a, b, ab, and o to the presence of the rh factor that is either present (pos.) or absent (neg.). use the information in the two - way table to complete the statement. the probability that a person has a positive rh factor given that he/she has type o blood is percent. there is a greater probability for a person to have a than a person to have a positive rh factor given type o blood.

	a	b	ab	o	total
pos.	.33	.09	.03	.37	.82
total	.40	.11	.04	.45	1.0

Explanation:

Step1: Recall conditional - probability formula

The formula for conditional probability is $P(A|B)=\frac{P(A\cap B)}{P(B)}$. Here, $A$ is the event of having a positive Rh - factor and $B$ is the event of having type O blood. $P(A\cap B)$ is the probability of having type O blood and positive Rh - factor, and $P(B)$ is the probability of having type O blood.

Step2: Identify values from the table

From the table, $P(A\cap B) = 0.37$ (the cell for type O and positive Rh - factor) and $P(B)=0.45$ (the total for type O blood).

Step3: Calculate the conditional probability

$P(A|B)=\frac{0.37}{0.45}\approx0.8222$. To convert to a percentage, we multiply by 100: $0.8222\times100 = 82.22\%$.

Answer:

82.22