Question

determine whether each statement is true or false.
\\(\frac{1}{4}(2^3 - 5 + 1) = 1\\) select choice
\\(8\left1 \div (4^2 - 10 + 2)\
ight = 1\\) select choice
\\(\frac{7^2 - 8(5) - 1}{8} + 12\left(\frac{1}{12}\
ight) = 1\\) select choice
options for each: false, true

Explanation:

Step1: Evaluate first expression

Calculate inside parentheses first: $2^3 -5 +1 = 8 -5 +1 = 4$.
Multiply by $\frac{1}{4}$: $\frac{1}{4} \times 4 = 1$.

Step2: Evaluate second expression

Calculate inside inner parentheses: $4^2 -10 +2 = 16 -10 +2 = 8$.
Compute division: $1 \div 8 = \frac{1}{8}$.
Multiply by 8: $8 \times \frac{1}{8} = 1$.

Step3: Evaluate third expression

Calculate numerator: $7^2 -8(5)-1 = 49 -40 -1 = 8$.
Divide by 8: $\frac{8}{8} = 1$.
Calculate second term: $12 \times \frac{1}{12} = 1$.
Sum the results: $1 + 1 = 2
eq 1$.

Answer:

1. True
2. True
3. False