Question

determine what elements are denoted by the following electron configurations:

1. 1s²2s²2p⁶3s²3p⁶
2. 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d⁸
3. ar4s²3d¹⁰4p³
4. xe6s²4f¹⁴5d⁶
5. rn7s²5f¹¹

part b - rules of electron configurations

Explanation:

Step1: Calculate the total number of electrons for each configuration

• For 11) \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}\):

The sum of electrons is \(2 + 2+6 + 2+6=18\). The element with 18 electrons is Argon (\(Ar\)).

• For 12) \(1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{6}5s^{2}4d^{8}\):

The sum of electrons: \(2+2 + 6+2+6+2+10+6+2+8 = 50\). The element with 50 electrons is Tin (\(Sn\)).

• For 13) \([Ar]4s^{2}3d^{10}4p^{3}\):

\(Ar\) has 18 electrons. Adding \(2 + 10+3=15\) more electrons. Total electrons \(18 + 15=33\). The element with 33 electrons is Arsenic (\(As\)).

• For 14) \([Xe]6s^{2}4f^{14}5d^{6}\):

\(Xe\) has 54 electrons. Adding \(2+14 + 6=22\) more electrons. Total electrons \(54+22 = 76\). The element with 76 electrons is Osmium (\(Os\)).

• For 15) \([Rn]7s^{2}5f^{11}\):

\(Rn\) has 86 electrons. Adding \(2+11 = 13\) more electrons. Total electrons \(86+13=99\). The element with 99 electrons is Einsteinium (\(Es\)).

Answer:

1. \(Ar\) (Argon); 12) \(Sn\) (Tin); 13) \(As\) (Arsenic); 14) \(Os\) (Osmium); 15) \(Es\) (Einsteinium)