Question

determine the electron geometry of $\ce{h_{3}coch_{3}}$ (skeletal structure $\ce{h_{3}coch_{3}}$) indicate the geometry about carbon atom trigonal planar tetrahedral linear pentahedral hexahedral submit request answer part f determine the molecular geometry of $\ce{h_{3}coch_{3}}$ (skeletal structure $\ce{h_{3}coch_{3}}$). indicate the geometry about carbon atom. trigonal planar trigonal pyramidal linear tetrahedral bent submit

Explanation:

Step1: Analyze electron geometry

For \(H_3COCH_3\), each carbon atom (except the carbon in double - bond situations, but here in \(H_3COCH_3\) (dimethyl ether), each carbon is \(sp^3\) hybridized. The number of electron - groups (bonding pairs) around each carbon is 4. According to VSEPR theory, when the number of electron - groups (\(n = 4\)), the electron geometry is tetrahedral.

Step2: Analyze molecular geometry

Since there are no lone pairs on the carbon atoms (each carbon is bonded to 4 other atoms or groups, 3 \(H\) atoms and 1 \(O\) - containing group for the methyl carbons), and based on VSEPR theory, when the number of bonding pairs (\(n = 4\)) and no lone pairs (\(l=0\)), the molecular geometry is also tetrahedral.

Answer:

Electron geometry: tetrahedral
Molecular geometry: tetrahedral