Question

determine the center and radius of the circle.
$(x - 4)^2+(y - 5)^2 = 81$
part: $0/2$
part 1 of 2
the center is $(square,square)$.

Explanation:

Step1: Recall the standard form of a circle equation

The standard form of a circle's equation is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center and \(r\) is the radius.

Step2: Identify \(h\) and \(k\)

For the equation \((x - 4)^2+(y - 5)^2=81\), comparing with \((x - h)^2+(y - k)^2=r^2\), we have \(h = 4\) and \(k=5\).

Answer:

The center is \((4,5)\)