Question

a delivery route starts at (-2, -1) and ends at (3, 4). how far is the straight-line route?
a. 5 units
b. √30 units
c. 4 units
d. √50 units

Explanation:

Step1: Identify coordinates

Start: $(x_1,y_1)=(-2,-1)$; End: $(x_2,y_2)=(3,4)$

Step2: Apply distance formula

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Step3: Calculate differences

$x_2-x_1=3-(-2)=5$; $y_2-y_1=4-(-1)=5$

Step4: Compute distance

$d=\sqrt{5^2+5^2}=\sqrt{25+25}=\sqrt{50}$

Answer:

d. $\sqrt{50}$ units