Question

△def is translated 5 units down to form its image.
complete the table to show the coordinates of the vertices of △def.
△def △def
d(-3,3) ?
e(-1,4) d(-1,-1)
f(2,1) d(-3,-2)
d(2,-4)

Explanation:

Step1: Recall the translation rule

When a point \((x,y)\) is translated \(k\) units down, the new coordinates are \((x,y - k)\). Here \(k = 5\).

Step2: Apply the rule to point \(D(-3,3)\)

For \(x=-3\) and \(y = 3\), \(y-5=3 - 5=-2\). So the coordinates of \(D'\) are \((-3,3 - 5)=(-3,-2)\).

Step3: Apply the rule to point \(E(-1,4)\)

For \(x=-1\) and \(y = 4\), \(y-5=4 - 5=-1\). So the coordinates of \(E'\) are \((-1,4 - 5)=(-1,-1)\).

Step4: Apply the rule to point \(F(2,1)\)

For \(x = 2\) and \(y=1\), \(y-5=1 - 5=-4\). So the coordinates of \(F'\) are \((2,1 - 5)=(2,-4)\).

Answer:

\(\triangle DEF\)	\(\triangle D'E'F'\)
\(E(-1,4)\)	\(E'(-1,-1)\)
\(F(2,1)\)	\(F'(2,-4)\)