Question

def func1(x, y):
return x - y
def func2(x, y):
return x * y
def func3(x, y):
return func1(y, x) + func2(5, x)
def main():
print(func3(1,2))

Explanation:

Step1: Substitute x = 1 and y = 2 into func3

$$func3(1,2)=func1(2,1)+func2(5,1)$$

Step2: Calculate func1(2,1)

According to the definition of func1, when \(x = 2\) and \(y = 1\), \(func1(2,1)=2 - 1=1\)

Step3: Calculate func2(5,1)

According to the definition of func2, when \(x = 5\) and \(y = 1\), \(func2(5,1)=5\times1 = 5\)

Step4: Calculate the result of func3(1,2)

Substitute the results of func1(2,1) and func2(5,1) into the expression of func3(1,2): \(func3(1,2)=1 + 5=6\)

Answer:

6