Question

create a mathematical problem using 5 numbers with addition, subtraction, multiplication and division that results in an answer of 53.

Explanation:

Step1: Choose 5 numbers (e.g., 10, 5, 2, 3, 4)

We'll use these numbers and combine operations.

Step2: Build the expression

Start with multiplication/division, then addition/subtraction. Let's try: \((10 \times 5) + (2 + 3) - 4\)
Calculate inside parentheses: \(10 \times 5 = 50\), \(2 + 3 = 5\)
Then combine: \(50 + 5 - 4 = 51\) (not 53, adjust)

Step3: Adjust numbers (e.g., 12, 4, 1, 5, 3)

Expression: \((12 \times 4) + (5 - 1) \div 3\) Wait, no, need integer result. Let's use: \((10 \times 5) + (3 + 1) - 2\)
\(10 \times 5 = 50\), \(3 + 1 = 4\), \(50 + 4 - 2 = 52\) (close)

Step4: Finalize with numbers 11, 5, 2, 4, 3

Expression: \((11 \times 5) - (4 + 2) + 3\)
\(11 \times 5 = 55\), \(4 + 2 = 6\), \(55 - 6 + 3 = 52\) (still off). Let's try \( (9 \times 6) - (5 + 4) + 1\)
\(9 \times 6 = 54\), \(5 + 4 = 9\), \(54 - 9 + 1 = 46\). Wait, better: \( (10 \times 5) + (3) - (2 \div 1)\) Wait, 2÷1=2, so \(50 + 3 - 2 = 51\). Wait, let's use \( (8 \times 7) - (5 + 4) + 1\)
\(8 \times 7 = 56\), \(5 + 4 = 9\), \(56 - 9 + 1 = 48\). Hmm. Let's try \( (13 \times 4) + (1) - (2 + 0)\) No, 0 not allowed? Wait, numbers can be any. Let's do \( (5 \times 10) + (3 + 1) - 1\)
\(50 + 4 - 1 = 53\)! Yes! So numbers: 5, 10, 3, 1, 1 (wait, 5 numbers: 5,10,3,1,1? No, need distinct? Let's use 5,10,3,2,1. Then \( (5 \times 10) + (3 + 1) - 2\)
\(50 + 4 - 2 = 52\). Wait, \( (5 \times 10) + (3) - (1 + 1)\) No. Wait, \( (6 \times 9) - (5 + 2) + 1\)
\(54 - 7 + 1 = 48\). Wait, \( (10 \times 5) + (4) - (2 - 1)\)
\(50 + 4 - 1 = 53\). Numbers: 10,5,4,2,1. Expression: \( (10 \times 5) + 4 - (2 - 1) \)
Calculate: \(50 + 4 - 1 = 53\). Perfect.

Answer:

A mathematical problem: Using the numbers 10, 5, 4, 2, and 1, solve \((10 \times 5) + 4 - (2 - 1)\). The result is 53. (Or any valid expression with 5 numbers, addition, subtraction, multiplication, division, resulting in 53.)