Question

the correct formula for titanium(iv) oxide is

ti2o4

ti4o

tio2

tio4

t2o

question 11
1 pts

the correct formula for carbon monoxide is

c2o

co2

co

ch4

cmno2

question 12
1 pts

the correct formula for lead(iv) nitrate is

pb2(no3)4

pb4no3

pb(no3)4

pb(no3)2

pbno3

Explanation:

• Titanium(IV) oxide: Titanium has a charge of \(+4\) (from (IV)), oxygen has a charge of \(-2\). Using the criss - cross method (swap the absolute values of the charges as subscripts), we get \(Ti_2O_4\), but we simplify the formula by dividing subscripts by their greatest common divisor (\(2\)), so \(TiO_2\).
• Carbon monoxide: “Mono -” means one. So one carbon (\(C\)) and one oxygen (\(O\)), formula is \(CO\).
• Lead(IV) nitrate: Lead has a charge of \(+4\) (from (IV)), nitrate (\(NO_3^-\)) has a charge of \(-1\). Using the criss - cross method, we get \(Pb(NO_3)_4\).

Answer:

• For titanium(IV) oxide: \(TiO_2\)
• For carbon monoxide: \(CO\)
• For lead(IV) nitrate: \(Pb(NO_3)_4\)