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the coordinate plane shows the graph of the quadratic function f(x). wh…

Question

the coordinate plane shows the graph of the quadratic function f(x). which of the following describes the graph of -3·f(x)?

Explanation:

Step1: Analyze transformation rules

For a function \( y = a \cdot f(x) \), if \( |a|>1 \), it's a vertical stretch; if \( 0<|a|<1 \), vertical compression. If \( a<0 \), reflect over x - axis. Here \( a=-3 \), so first reflect \( f(x) \) over x - axis, then vertically stretch by factor 3.

Step2: Analyze original graph

Original \( f(x) \) is a parabola opening up (since coefficient of \( x^{2} \) is positive), vertex at \( (0, - 9) \) (from graph, lowest point at y=-9), x - intercepts at \( x=-1 \) and \( x = 4 \)? Wait, no, looking at grid, x - intercepts at \( x=-1 \)? Wait, the original graph crosses x - axis at \( x=-1 \)? Wait, no, the grid: x from -16 to 16, y from -16 to 16. The original parabola: when x = -1, y=0? Wait, no, looking at the graph, the roots (x - intercepts) are at \( x=-1 \) and \( x = 4 \)? Wait, no, the graph crosses x - axis at x=-1? Wait, no, the left x - intercept: when x=-1, y=0? Wait, the grid lines: each square is 1 unit. So original \( f(x) \): vertex at (0, - 9), opens up, x - intercepts at x=-1 and x = 4? Wait, no, when x = -1, y=0; x = 4, y=0? Wait, no, let's check: when x=0, y=-9. So original \( f(x)=a(x - 0)^{2}-9=ax^{2}-9 \). When y = 0, \( ax^{2}-9 = 0\), \( x^{2}=\frac{9}{a} \). From graph, when x = 3, y=0? Wait, maybe I misread. Anyway, the key is transformation: \( - 3f(x) \) will reflect over x - axis (so opens down) and stretch vertically by 3. So vertex of original at (0, - 9), after reflection: (0, 9), then stretch by 3: (0, 27). X - intercepts remain same (since multiplying by - 3 doesn't change where y = 0, because \( - 3f(x)=0\) when \( f(x)=0 \)). The direction: original opens up, new opens down. Vertical stretch: each y - value is multiplied by - 3, so the graph is reflected over x - axis and vertically stretched by a factor of 3.

Answer:

The graph of \( - 3\cdot f(x) \) is a parabola that opens downward, is vertically stretched by a factor of 3 compared to \( f(x) \), has the same x - intercepts as \( f(x) \), and its vertex is at \( (0, 27) \) (since original vertex y - coordinate is - 9, \( - 3\times(-9)=27 \)) while being reflected over the x - axis (so opening direction changes from up to down).