QUESTION IMAGE
Question
consider what happens when you rotate line segment kl around two different points.
if we rotate line segment kl 180 degrees around point t, where will its image be taken?
Step1: Recall the property of 180 - degree rotation
A 180 - degree rotation about a point \(T\) maps a point \(P(x,y)\) to \(P'(-x + 2a,-y+2b)\) if \(T=(a,b)\). For a line segment \(KL\), when we rotate it 180 degrees about a point \(T\) on the line segment (in the first case, \(T\) is on the line segment \(KL\)), the image of the line segment \(KL\) will be collinear with the original line segment \(KL\) and \(T\) will still be on the image of the line segment.
Step2: Analyze each option
- In the top - left option: Since \(T\) is on the line segment \(KL\), after a 180 - degree rotation about \(T\), the line segment \(KL\) is mapped to itself (because for any point \(X\) on \(KL\), if \(TX = d\), then the rotated point \(X'\) is such that \(TX'=d\) and \(X,X'\) are on opposite sides of \(T\)).
- In the top - right option: \(T\) is not on the line segment \(KL\). A 180 - degree rotation about a non - collinear point \(T\) will not map \(KL\) to a position where \(T\) is on the line segment (the original line segment \(KL\) and its image after 180 - degree rotation about a non - collinear point \(T\) will form a parallelogram - like shape, not a straight line passing through \(T\)).
- In the bottom - left option: The orientation and the position of the line segment with respect to \(T\) do not satisfy the 180 - degree rotation property (the lengths and the collinearity conditions are not met).
- In the bottom - right option: If \(T\) is on the line segment \(KL\), after a 180 - degree rotation, the line segment should be in the same straight line. Here, the line segment in the bottom - right option is parallel but not collinear (if \(T\) is on the original line segment \(KL\) and we rotate 180 degrees about \(T\), collinearity must hold).
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The top - left option.