Question

consider reaction no. 4. what are the values for the balanced equation coefficients? input a single numeric value in the order of the reactants and products, reading from left to right.
format: the answer must be entered with no spaces or commas, i.e., write it as a numeric value only. you must input any \1\ values also. for example, 2 al + 3 o2 --> 2 al2o3 inputs as 232 note: do not worry if the app adds commas.

1. alf3 + na2so4 --> naf + al2(so4)3.
2. p + o2 → p4o10
3. agf + cacl2 → agcl + caf2
4. b2o3 → b + o2
5. kbr + cl2 → kcl2 + br2
6. pb(no3)2 + ki → kno3 + pbi2
7. al2(so4)3 + bacl2 → baso4 + alcl3
8. nh3 → h2 + n2
9. c2h2 + o2 → co2 + h2o
10. ca + fe2o3 → fe + cao

this problem can be solved by dimensional analysis as the primary method, formula where permitted, or simple math. using ratio and proportion methods is not allowed. be sure to show the formula on homework and exams.
show work here as a file upload in the last question. be sure to report the units for all values when showing your work. keys will be posted for exemplary practice problems.
you must show work on the exams. practice showing the calculator answer and the sig figs answer.

Explanation:

Step1: Balance the oxygen atoms

To balance the oxygen atoms in the reaction $B_2O_3
ightarrow B + O_2$, we need to find the least - common multiple of 3 (from $B_2O_3$) and 2 (from $O_2$). The least - common multiple of 3 and 2 is 6. So we put a 2 in front of $B_2O_3$ and a 3 in front of $O_2$: $2B_2O_3
ightarrow B + 3O_2$.

Step2: Balance the boron atoms

Now, with 2 moles of $B_2O_3$, we have 4 moles of boron atoms on the left - hand side. So we put a 4 in front of B on the right - hand side. The balanced equation is $2B_2O_3
ightarrow4B + 3O_2$.

Answer:

243