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consider an isotope of carbon that has 7 neutrons. (6 pts) a. write thi…

Question

consider an isotope of carbon that has 7 neutrons. (6 pts)
a. write this isotopes notation in nuclear form.
b. write this isotopes notation in hyphen form.
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Explanation:

Step1: Determine the atomic number of carbon

Carbon has an atomic number \(Z = 6\) (number of protons).

Step2: Calculate the mass number \(A\)

Mass number \(A=\) number of protons \(+\) number of neutrons. Given \(Z = 6\) (protons) and number of neutrons \(=7\), then \(A=6 + 7=13\).

Step3: Write the nuclear - form notation

The nuclear - form notation for an isotope is \(\ce{^{A}_{Z}X}\), where \(X\) is the chemical symbol. For carbon (\(X = C\)), \(Z = 6\) and \(A = 13\), so it is \(\ce{^{13}_{6}C}\).

Step4: Write the hyphen - form notation

The hyphen - form notation is element - mass number. For carbon with mass number \(A = 13\), it is carbon - 13.

Answer:

a. \(\ce{^{13}_{6}C}\)
b. carbon - 13