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consider the force diagrams below for five different situations. think!…

Question

consider the force diagrams below for five different situations. think! there may be more than one answer!

which of the object(s) above could be moving to the right at a constant speed?

Explanation:

Step1: Analyze the condition for constant - speed motion

An object moving at a constant speed has a net force of zero in both the horizontal and vertical directions (Newton's first law: \(F_{net}=ma\), when \(a = 0\), \(F_{net}=0\)).

  • Vertical direction: \(F_{norm}=F_{grav}\) (balanced forces in the vertical direction).
  • Horizontal direction: If there is a frictional force (\(F_{frict}\)), then \(F_{app}=F_{frict}\) (balanced forces in the horizontal direction).

Step2: Analyze each object

  • Object A: Only vertical forces (\(F_{norm}\) and \(F_{grav}\)). No information about horizontal motion. But if we assume no horizontal forces (or no acceleration in the horizontal direction), it can move at a constant speed (e.g., if it was already in motion and there is no un - balanced horizontal force to change its state).
  • Object B: \(F_{app}\) is un - balanced in the horizontal direction (\(F_{frict}=0\) in the diagram). So, \(F_{net,x}=F_{app}

eq0\). By Newton's second law \(a=\frac{F_{net}}{m}\), it will have an acceleration in the direction of \(F_{app}\) and not move at a constant speed.

  • Object C: In the vertical direction \(F_{norm}=F_{grav}\), and in the horizontal direction \(F_{app}=F_{frict}\). So, \(F_{net,x}=F_{app}-F_{frict}=0\) and \(F_{net,y}=F_{norm}-F_{grav}=0\). The object can move at a constant speed.
  • Object D: In the vertical direction \(F_{norm}=F_{grav}\), but \(F_{app}>F_{frict}\). So, \(F_{net,x}=F_{app}-F_{frict}>0\). By Newton's second law \(a=\frac{F_{net}}{m}\), it will have an acceleration in the direction of \(F_{app}\) and not move at a constant speed.
  • Object E: \(F_{frict}\) is un - balanced in the horizontal direction (\(F_{app}=0\) in the diagram). So, \(F_{net,x}=F_{frict}

eq0\). By Newton's second law \(a = \frac{F_{net}}{m}\), it will have an acceleration in the direction of \(F_{frict}\) and not move at a constant speed.

Answer:

A. Object A, C. Object C