Question

consider the following incomplete method. method findnext is intended to return the index of the first occurrence of the value val beyond the position start in array arr. // returns arr.length if val is not found after position start;
public int findnext(int arr, int val, int start) {
int pos = start + 1;
while ( / condition / ) {
pos++;
}
return pos;
}

for example, consider the following code segment.

int arr = {11, 22, 100, 33, 100, 11, 44, 100};
system.out.println(findnext(arr, 100, 2));

the execution of the code segment should result in the value 4 being printed.

which of the following expressions could be used to replace / condition / so that findnext will work as intended?

a.
(pos < arr.length) && (arrpos != val)

b.
(arrpos != val) && (pos < arr.length)

Explanation:

To determine the correct condition, we analyze the method's purpose: find the first occurrence of val after start. The loop should continue while two conditions hold: 1) pos is within the array bounds (pos < arr.length), and 2) the current element arr[pos] is not equal to val (so we keep searching).

• For option A: (pos < arr.length) && (arr[pos] != val) checks bounds first. If pos is out of bounds, the second condition is not evaluated (short - circuiting), preventing array index errors. This ensures we only check arr[pos] when pos is valid.
• For option B: (arr[pos] != val) && (pos < arr.length) checks the element first. If pos is out of bounds, accessing arr[pos] will cause an array index out - of - bounds error before checking the bounds condition.

In the example, when start = 2, pos starts at 3. We need to loop until we find 100 or reach the end. Option A's order of conditions (bounds first) is safe and correct.

Answer:

A. \((\text{pos} < \text{arr.length}) \&\& (\text{arr}[\text{pos}] != \text{val})\)